- #1

ihearyourecho

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## Homework Statement

A single conducting loop of wire has an area of 7.2×10

^{−2}m

^{2}and a resistance of 120 ohms. Perpendicular to the plane of the loop is a magnetic field of strength 0.50 T.

At what rate must this field change if the induced current in the loop is to be 0.39A?

## Homework Equations

emf=(-NdeltaI

_{B})/(deltat)

Rate of change = emf/-N

## The Attempt at a Solution

emf=(-NdeltaI

_{B})/(deltat)

Rate of change = emf/-N

It's a single loop, so N should be 1

Rate of change - emf/-1

emf=v=IR

Rate of change = -IR

Rate of change = -(.39A)*120ohms=-46.8

This isn't right though.

Thanks for the help :)

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