Rate of return with logs [engineering economics]

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SUMMARY

The discussion focuses on calculating the rate of return on an investment using the Single Payment Compound Interest Formula. The original purchase price of a Picasso painting in 1903 was $600, and it was sold in 1995 for $29,152,000. The formula F = P(1+i)^n is utilized, where F represents the future value, P is the present value, n is the number of interest periods, and i is the interest rate. The participant struggles to isolate the interest rate i from the logarithmic equation derived from the formula.

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Homework Statement



In 1903, a Picasso painting was purchased for $600. The family of the original owner sold the painting in 1995 for $29,152,000. What rate of return (interest) did the family receive on the investment?

Homework Equations



Single Payment Compound Interest Formula:

F = P(1+i)n

where,

F= a future some of money (future value)
P= a present sum of money
n= number of interest periods
i = interest rate per interest period.

The Attempt at a Solution



solve for i:

F = P(1+i)n
F/P = (1+i)n
log(F/P) = n log (1+i)

This is as far as I get. I know that n log (1+i) does not equal n log 1 + n log i, but I don't know what to do to isolate the i. I can't just divide both sides by n log because there is no such thing as n log. I thought about moving n log (1+i) to the left side and setting the equation to zero, but I didn't get anywhere with that either.
 
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Think about how you would invert a logarithmic function:

[tex]y = \log x \Leftrightarrow x = {10^y}[/tex]
 
get rid of the power of n by raising both sides by 1/n. i don't think that log trick you're pulling is even accurate
 

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