Calculating Energy Dissipation in an RC Circuit

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SUMMARY

The discussion focuses on calculating energy dissipation in an RC circuit involving a 50V battery, a 125 ohm resistor, and a 20uF capacitor. When the switch is flipped to position b, the energy dissipated by the 50 ohm resistor is determined to be 23 mJ. Key equations utilized include the time constant (RC), energy stored in the capacitor (Ucap=0.5CV^2), and the relationship between current and resistance (V=IR). The solution involves calculating the total charge transferred and integrating the power dissipation over time.

PREREQUISITES
  • Understanding of RC circuits and time constants
  • Familiarity with capacitor energy equations (Ucap=0.5CV^2)
  • Knowledge of Ohm's Law (V=IR)
  • Ability to perform integration for power calculations
NEXT STEPS
  • Study the derivation of the time constant in RC circuits
  • Learn about energy dissipation in resistive circuits
  • Explore integration techniques for calculating power over time
  • Investigate the behavior of capacitors in transient analysis
USEFUL FOR

Students studying electrical engineering, circuit designers, and anyone interested in understanding energy dissipation in RC circuits.

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Homework Statement


The switch in the figure (Intro 1 figure) has been in position a for a very long time. It is suddenly flipped to position b for 1.25 ms, then back to a. How much energy is dissipated by the resistor?

the circuit for a is 50V battery, 125 ohm resistor and 20uF capacitor. The circuit for b is the 20uF capacitor and the 50 ohm resistor.

Homework Equations



Time constant=RC, Ucap=0.5CV^2, V=IR, Q=CV, i don't know I've tried others too

The Attempt at a Solution



I know the capacitor will be at 50V. I found time constant and current and charge and tried so see if i=i(max)e^(-t/RC) would work and tried to relate it back to energy but it didn't. The answer is 23 mJ.
 
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First of all find the total charge in the first capacitor when the switch in position a.
Find the total charge transferred to second capacitor in 1.25 ms when the switch is in b position. dQ/dt will give you the current in the resistance. Find the average current I and I^2R will give you the power dissipation.
 
Last edited:
To get answer integrate I^2R dt. Integrating the average current squared is an approximation...
 

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