RC circuit and kirchoff's loop rule

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The discussion centers on understanding why the correct answer to Question 27 is A, despite initial confusion suggesting it should be B. The application of Kirchhoff's Loop Rule indicates that after a long time, the current in the inner left loop becomes zero, leading to the equation V(battery) = Q/C. The capacitor, treated as an open circuit at DC, complicates the interpretation of its relationship with the battery. By analyzing two loops, the conclusion is reached that Vc equals Vb/2, ultimately leading to the correct charge equation Q = C*Vb/2. This highlights the importance of correctly applying circuit rules and understanding capacitor behavior in steady-state conditions.
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I need help with Question 27 specifically. The correct answer is A, but I don't understand why.

I thought it would be B according to Korkoff's Loop rule of the inner left loop, where current of inner left loop is 0 after switch is closed after a long time. So V(battery) - Q/C = 0 so V(battery) =Q/C
 
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Let's see here, it can't be a because the cap isn't in parallel with the battery. A capacitor has infinite impedance at DC, so after an infinite time it can be modeled as an open circuit.

So loop 1)
Vb-Vc-IR=0
Loop 2)
Vb-2IR=0

combine to get
Vb-Vc-Vb/2=0

so
Vc=Vb/2

Vc=Q/C

so Vb/2=Q/C

Q=C*Vb/2

Voila.
 

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