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Reaction of tritium and deuterium
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[QUOTE="skrat, post: 4718813, member: 455703"] Hmmm, your idea my work, yet I have found out what I was supposed to do. The idea is too ignore semi empirical mass formula but to rather look in the table and find out that: ##m(n)=1.008665 au## ##m(D)=2.014102 au## ##m(T)=3.016050 au## and ##m(He)=4.002603 au##. This now gives me the right result ##W=c^2[m(He)+m(n)-m(T)-m(D)]=17.6MeV## [/QUOTE]
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Reaction of tritium and deuterium
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