The net force exerted on a 3.5-kg block is shown in the figure as a function of time. How far does the block travel in the first 11.0 s? Assume that the motion is one dimensional and that the velocity of the block at time t= 0 s is 0 m/s.
Vf^2 = Vi^2 + 2ad
The Attempt at a Solution
I figured that I could use the force on the graph so I used F=ma. Using the first point of the graph, I got 4 N = (3.5 kg)a, solved for a and got 1.14 m/s^2. Since I'm trying to find distance, I tried using Vf^2 = Vi^2 + 2ad but here's where I got stuck. Initial velocity would be 0 m/s but for final velocity, I'm not sure where I would get that number from. Am I headed in the right direction with this problem?
Also, this type of graph is kind of confusing to read for me. If the y-axis in this problem was labeled acceleration (ax) instead of F(N), a straight horizontal line from 0 to 2 seconds would be constant acceleration then from 2 to 6 seconds, it would be zero acceleration?
Any help would be amazing and immensely appreciated.
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