Real Value of x in Complex Equation?

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SUMMARY

The discussion focuses on determining the real value of x in the equation Re(10 / (x + 4i)) = 1. The transformation of the equation leads to (10x - 40i) / (x^2 + 16) = 1. To isolate the real part, the equation is expressed as 10x/(x^2 + 16) - 40i/(x^2 + 16). Setting the real part equal to 1 allows for solving for x, which is the crux of the problem.

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Homework Statement


Decide the real value of x making Re(10 / x+4i) = 1


Homework Equations


I know that you can extend the equation with x-4i.


The Attempt at a Solution


But then the equation looks like this: (10x-40i) / (x^2 + 16) = 1
I don't know how to get rid of the -40i to make it into a real equation.

Any help would be valuable!
 
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[tex]\frac{10x-40i}{x^2+ 16}= \frac{10x}{x^2+16}-i\frac{40}{x^2+ 16}[/tex]
 
It says the real part of (10x - 40i)/(x^2 + 16) = 10x/(x^2+16) - 40i/(x^+16). Take the real part of that and set it equal to 1, and solve for x.
 

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