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Complex numbers in the form a+bi

  1. May 24, 2016 #1
    1. The problem statement, all variables and given/known data

    How would I go about solving 1/z=(-4+4i)

    The answer that I keep on getting is wrong

    3. The attempt at a solution

    What I did

    z=1/(-4+4i)x(-4-4i)/(-4-4i)

    z=(-4-4i)/(16+16i-16i-16i^2)

    z=(-4-4i)/32

    z=-1/8-i/8

    This is the answer that I got however it says that it is wrong. I am unsure what else I can do

    Thanks for any help
     
  2. jcsd
  3. May 24, 2016 #2

    ehild

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    Homework Helper
    Gold Member

    Your result is right, but you might write it in the form ##-\frac{1}{8}- \frac{1}{8} i##
     
  4. May 24, 2016 #3
    Thanks! I thought I was right, the online quiz that we have must have a mistake then
     
  5. May 27, 2016 #4
    Complex numbers ##z##, have to be expressed in the form ##z= a+bi##, where ##a, b##, are real numbers, this was missing in your solution, the ##"i"##
     
  6. May 27, 2016 #5

    Mark44

    Staff: Mentor

    No, it was there. This is what the OP wrote:
     
  7. May 27, 2016 #6

    ehild

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    Homework Helper
    Gold Member

    Maybe you should write 0.125 instead of 1/8.
     
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