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Complex numbers in the form a+bi

  • #1
52
0

Homework Statement



How would I go about solving 1/z=(-4+4i)

The answer that I keep on getting is wrong

The Attempt at a Solution


[/B]
What I did

z=1/(-4+4i)x(-4-4i)/(-4-4i)

z=(-4-4i)/(16+16i-16i-16i^2)

z=(-4-4i)/32

z=-1/8-i/8

This is the answer that I got however it says that it is wrong. I am unsure what else I can do

Thanks for any help
 

Answers and Replies

  • #2
ehild
Homework Helper
15,427
1,823

Homework Statement



How would I go about solving 1/z=(-4+4i)

The answer that I keep on getting is wrong

The Attempt at a Solution


[/B]
What I did

z=1/(-4+4i)x(-4-4i)/(-4-4i)

z=(-4-4i)/(16+16i-16i-16i^2)

z=(-4-4i)/32

z=-1/8-i/8

This is the answer that I got however it says that it is wrong. I am unsure what else I can do

Thanks for any help
Your result is right, but you might write it in the form ##-\frac{1}{8}- \frac{1}{8} i##
 
  • #3
52
0
Your result is right, but you might write it in the form ##-\frac{1}{8}- \frac{1}{8} i##
Thanks! I thought I was right, the online quiz that we have must have a mistake then
 
  • #4
chwala
Gold Member
618
42
Complex numbers ##z##, have to be expressed in the form ##z= a+bi##, where ##a, b##, are real numbers, this was missing in your solution, the ##"i"##
 
  • #5
33,267
4,966
Complex numbers ##z##, have to be expressed in the form ##z= a+bi##, where ##a, b##, are real numbers, this was missing in your solution, the ##"i"##
No, it was there. This is what the OP wrote:
z=-1/8-i/8
 
  • #6
ehild
Homework Helper
15,427
1,823
Thanks! I thought I was right, the online quiz that we have must have a mistake then
Maybe you should write 0.125 instead of 1/8.
 

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