Recombination Lines - Astrophysics

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Homework Help Overview

The discussion revolves around the calculation of frequency shifts in atomic transitions for an atom X, specifically focusing on high-n energy levels and their corresponding frequencies near 142 MHz. The problem involves understanding the energy levels defined by the formula ##E_n = -\mu \frac{(\alpha c)^2}{n^2}## and the implications of using different units for the fine structure constant.

Discussion Character

  • Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants explore the derivation of the frequency shift and question the validity of the energy level formula. There is a discussion about unit consistency and the implications of using different forms of the fine structure constant. Some participants express confusion regarding discrepancies between calculated values of n and those found in literature.

Discussion Status

The conversation is ongoing, with participants providing insights and questioning assumptions about the energy level formula. There is an acknowledgment of a potential error in the formula, with suggestions to consider a factor of 1/2 to align with known results. However, no consensus has been reached regarding the correct approach or resolution of discrepancies.

Contextual Notes

Participants note issues related to unit conversions and the dimensionality of constants, which may affect the calculations. There is also mention of specific literature references that provide different values for n, indicating a need for further exploration of these sources.

BOAS
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Homework Statement



For an atom X, the high-n levels have energies ##E_n = -\mu \frac{(\alpha c)^2}{n^2}## with ##\alpha = \frac{e^2}{\hbar c}##

Find the frequency shift ##\nu_{Hen\alpha} - \nu_{Hn\alpha}## for ##n\alpha## giving a transition frequency near 142MHz

(The notation here means that the electron moves by one energy level)

Homework Equations

The Attempt at a Solution


[/B]
##E_f - E_i = -\mu \frac{(\alpha c)^2}{(n-1)^2} + \mu \frac{(\alpha c)^2}{n^2}##

## = \mu (\alpha c)^2 (\frac{1}{n^2} - \frac{1}{(n-1)^2}) = h\nu##

rearranging and simplifying leads to

##\frac{1-2n}{(n-1)^2 n^2} = \frac{h \nu}{\mu (\alpha c)^2}##

Using a simplification I found justified here: http://www.cv.nrao.edu/course/astr534/Recombination.html

##\frac{1-2n}{(n-1)^2 n^2} \approx \frac{2}{n^3}##

which leads to

##n \approx (\frac{2 \mu (\alpha c)^2}{h \nu})^{\frac{1}{3}}##

solving for n using the value of the fine structure constant given in the question (which is in cgs units I believe), I get nonsense answers of ##n < 1##.

Using the value of ##\alpha = \frac{ke^2}{\hbar c}## in SI units, I get values of n that produce the correct frequency when plugged back into my formula, but do not agree with radio combination lines that I looked up here: http://adsabs.harvard.edu/full/1968ApJS...16..143L

For example, using the fine structure constant in SI units, for Hydrogen I find ##n = 452##, which when plugged into

##\nu = \frac{\mu (\alpha c)^2}{h} (\frac{1}{n^2} - \frac{1}{(n-1)^2})##

I get ##\nu = 142.5MHz##, but from the above link I find that the transition should correspond to n=359.

I'm really struggling to get my head around where the discrepancy lies.

Thank you in advance for any help you can give!

EDIT - Ok, so I was using the wrong units for ##e## which solves my concerns about the fine structure's value, which is dimensionless. However, I am still stuck regarding the discrepancy between my calculated n values, and those I have found in the literature.
 
Last edited:
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BOAS said:

Homework Statement



For an atom X, the high-n levels have energies ##E_n = -\mu \frac{(\alpha c)^2}{n^2}##
I believe you are off by a factor of 2 in this formula.
 
TSny said:
I believe you are off by a factor of 2 in this formula.

A factor of 1/2 would make more sense I think - It would recover the ground state energy of Hydrogen and make my solutions for n match up with the recombination lines I linked to in my post.
 
Yes.
 

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