Recovering a function using the inverse fourier transform

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SUMMARY

The discussion centers on the implications of the sign of the argument in the Fourier transform and its inverse. Specifically, it establishes that if the sign of the argument remains the same for both the forward and inverse Fourier transforms, the original function f(t) cannot be recovered. The integral expressions for the Fourier transform, given by $$F(\omega) = \frac{1}{\sqrt{2\pi}}\int_{-\infty}^\infty f(t)e^{-i\omega t}\,dt$$ and the inverse transform, $$\frac{1}{\sqrt{2\pi}}\int_{-\infty}^\infty F(\omega)e^{-i\omega t}\,d\omega$$ are crucial in demonstrating this fact.

PREREQUISITES
  • Understanding of Fourier Transform and Inverse Fourier Transform
  • Familiarity with complex exponentials in integrals
  • Knowledge of delta functions and their properties
  • Basic calculus, particularly integration techniques
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  • Study the properties of the Fourier Transform and its inverse
  • Explore the implications of the delta function in signal processing
  • Learn about the Fourier inversion theorem and its conditions
  • Investigate the role of complex exponentials in Fourier analysis
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Students and professionals in mathematics, physics, and engineering who are working with signal processing, particularly those focusing on Fourier analysis and its applications.

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Homework Statement


The argument of the kernel of the Fourier transform has a different sign for the forward and inverse transform. For a general function, show how the original function isn’t recovered upon inverse transformation if the sign of the argument is the same for both the forward and inverse transform.


Homework Equations


The Fourier and the Inverse Fourier transform integrals


The Attempt at a Solution


Do I need to prove the inverse Fourier theorem or is there a simpler solution?
One attempt that I have seen at recovering the original function using the inverse Fourier transform formula integrates the exponent part to a sin(Mx)/x type function, which is then shown to approach the delta function as M approaches ∞.
 
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Let
$$F(\omega) = \frac{1}{\sqrt{2\pi}}\int_{-\infty}^\infty f(t)e^{-i\omega t}\,dt.$$ The problem is simply asking you to show that if you calculate
$$\frac{1}{\sqrt{2\pi}}\int_{-\infty}^\infty F(\omega)e^{-i\omega t}\,d\omega,$$ you do not recover f(t). Just plug the expression for F(ω) into the second integral and calculate away.
 

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