Rectangular waveguide cavity - Maximum E field

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SUMMARY

The discussion focuses on calculating the maximum electric field strength in a rectangular waveguide cavity resonator operating at 1.6 GHz, with an input power of 200W and supporting the TE101 mode. The cavity dimensions are specified as 0.131mm x 0.65mm x 0.134mm, constructed with lossy copper walls having a conductivity of 5.8 x 107 S/m. Participants discuss estimating the Q-factor and power loss in the conducting walls to derive the electric field strength using the formula Eo2 = (16 * Q * Pc) / (2 * ωo * ε * a * b * d), although there is uncertainty regarding its accuracy.

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m_niz
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Hi,

I am trying to calculate maximum E-field strength in a rectangular waveguide cavity resonator at 1.6GHz. The input power is 200W while the resonator should wsupport TE101 mode. cavity dimensions are 0.131mmx0.65mmx0.134mm (WxHxL) having lossy walls made up of copper with conductivity of 5.8x10^7.

Is there any equation or procedure that can lead me to this solution? I have adopted a way to calculate Q factor, assume power loss in guide walls as 10W and then calculate Eo. Is it the right approach?

Thanks
 
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Hi m_niz,

I have a similar problem and I was wondering if you have finally found out how to estimate the maximum E field for a given input power. I would appreciate if yuo share it with me.

Thanks
 
Hi rama-lama,

I am failed to figure out a direct method for such calculation. The only way I found is to estimate the Q-factor, then by assuming power loss in the conducting walls(Pc) (and in the filled dielectric if that is the case), I calculated E-field using:

Eo^2=(16*Q*Pc)/(2*wo*ε*a*b*d)

I am not very sure that it gives the right value though.
 

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