Recurrence relation oddball one

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SUMMARY

The recurrence relation T(n) = 2T(n-1) with the base case T(1) = 1 leads to an exponential growth pattern. The iterative expansion shows that T(n) can be expressed as T(n) = 2^n - 1, which can be derived by recognizing the pattern in the iterations. The discussion emphasizes the importance of identifying patterns in recursive definitions to convert them into summation forms for easier analysis.

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illidari
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Homework Statement



T(n) = 2T(n-1)
T(1)=1

The Attempt at a Solution



I am trying to show the iterations.

T(n) = 2T(n-1)
T(n) = 22T(n-2)
T(n) = 222T(n-3)

Is this the right track? Where the result would be 22222...1eventually?

The problem just feels awkward D:

If my answer is right is there any way to get this into a summation form?
 
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Usually for these you start with a small n (or your base case) and start to look for a pattern.

T(1) = x
T(2) = x + something
T(3) = x + T(2)
.
.
.
T(n) = The summation of some pattern you found

Give that a try instead of looking for a pattern at step n.
 

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