Integrate sin(adsbygoogle = window.adsbygoogle || []).push({}); ^{2}(x)cos^{4}(x)dx using reduction formulas?

My book says integral sin^{2}(x)cos^{4}(x)dx= integral cos^{4}(x)-integral cos^{6}x dx

Now the reduction formula for n=6

for integral cos^{6}(x)dx= (1/6)cos^{5}(x)sinx+(5/6) integral cos^{4}(x)dx

Here is the part I don't get: It then says :

sin^{2}(x)cos^{4}(x)dx

=(-1/6)cos^{5}(x)sinx+(1/6) integral cos^4(x)dx

I don't get how the 5/6 becomes 1/6 or why 1/6 becomes -1/6 if that makes any sense? Any help would be great! I've been looking at it for awhile, but Im not seeing it for some reason.

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# Reduction formulas for integral of sin and cos

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