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- Thread starter gandharva_23
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[tex] c^2 \frac{\partial^2 y}{\partial x^2} = \frac{\partial^2 y}{\partial t^2} [/tex]

a general solution is

[tex] y(x,t) = y_1(x-ct) + y_2(x+ct) [/tex]

where c is the wavespeed and [itex] y_1(.), y_2(.) [/itex] can be anything and have to be determined by initial conditions. [itex] y_1(x-ct) [/itex] is a wave moving in the +x direction and [itex] y_2(x+ct) [/itex] is a wave moving in the -x direction and the two waves just add up (superimpose). now let's say that your string is anchored at x=0. that means that

[tex] y(0,t) = y_1(-ct) + y_2(ct) = 0 [/tex]

for all time t. now about the only way for that to happen is if

[tex] y_1(-ct) = -y_2(ct) [/tex]

that means, at x=0, that the wave that is moving in one direction has to be the exact negative of the wave moving in the other direction for them to add to zero and they have to add to zero because of the "fixed support". reversing the polarity is the same as a phase change of [itex] \pi [/itex] radians.

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Meir Achuz

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