Reflection of a mechanical wave

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SUMMARY

The reflection of a mechanical wave at a fixed support results in a phase change of π radians. This phenomenon can be understood through the one-dimensional wave equation, described by the differential equation c² ∂²y/∂x² = ∂²y/∂t². The general solution y(x,t) = y₁(x-ct) + y₂(x+ct) demonstrates that for a wave on a stretched string anchored at x=0, the incident wave must be the negative of the reflected wave to satisfy the boundary condition y(0,t) = 0. This negative relationship confirms the phase inversion upon reflection.

PREREQUISITES
  • Understanding of the one-dimensional wave equation
  • Familiarity with wave superposition principles
  • Knowledge of boundary conditions in wave mechanics
  • Basic concepts of phase change in wave phenomena
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  • Study the derivation of the one-dimensional wave equation
  • Explore wave reflection and transmission at boundaries
  • Investigate the concept of phase shifts in different wave types
  • Learn about the implications of fixed and free boundary conditions in wave behavior
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Physics students, educators, and professionals in wave mechanics, particularly those focusing on mechanical waves and their properties in various media.

gandharva_23
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when a mechanical wave is reflected by a fixed support it experiences a phase change of pi ... without getting into maths can i qualitatively prove this ? i cannot analyse how the forces will be acting .
 
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let's assume this is a one-dimensional wave problem (wave on a stretched out string). the diff eq. describing it is likely:

[tex]c^2 \frac{\partial^2 y}{\partial x^2} = \frac{\partial^2 y}{\partial t^2}[/tex]

a general solution is

[tex]y(x,t) = y_1(x-ct) + y_2(x+ct)[/tex]

where c is the wavespeed and [itex]y_1(.), y_2(.)[/itex] can be anything and have to be determined by initial conditions. [itex]y_1(x-ct)[/itex] is a wave moving in the +x direction and [itex]y_2(x+ct)[/itex] is a wave moving in the -x direction and the two waves just add up (superimpose). now let's say that your string is anchored at x=0. that means that

[tex]y(0,t) = y_1(-ct) + y_2(ct) = 0[/tex]

for all time t. now about the only way for that to happen is if

[tex]y_1(-ct) = -y_2(ct)[/tex]

that means, at x=0, that the wave that is moving in one direction has to be the exact negative of the wave moving in the other direction for them to add to zero and they have to add to zero because of the "fixed support". reversing the polarity is the same as a phase change of [itex]\pi[/itex] radians.
 
The easiest way to see the pi pahse change is that the incident and reflected wave mus cancel at the fixed wall. This means the reflected wave must be the negative of the incident wave.
 

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