Refraction at grazing incidence

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SUMMARY

The discussion centers on the concept of refraction at grazing incidence, specifically when light transitions from air into a glass cube. The key equation used is Snell's Law, represented as n1sinθ1 = n2sinθ2, where n1 is the refractive index of air (1), and n2 is that of glass (1.55). The angle of incidence (θ1) is defined as 90 degrees, leading to a calculated angle of refraction (θ2) of approximately 48.5 degrees. The participants clarify that grazing incidence means the angle is slightly less than 90 degrees, allowing the light to enter the glass rather than traveling straight into the water.

PREREQUISITES
  • Understanding of Snell's Law for refraction
  • Knowledge of refractive indices (e.g., air and glass)
  • Familiarity with the concept of angles of incidence and refraction
  • Basic principles of light behavior at interfaces
NEXT STEPS
  • Study the derivation and applications of Snell's Law in optics
  • Explore the concept of critical angle and total internal reflection
  • Learn about the behavior of light in different media, including water and glass
  • Investigate graphical methods for illustrating light paths through various materials
USEFUL FOR

Students studying optics, physics educators, and anyone interested in understanding the principles of light refraction and its applications in real-world scenarios.

nilic1
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Homework Statement



I have a problem with the question in the attachment below. I have no idea on how to proceed as I thought that the ray of light would continue to travel in a straight line with no refraction whatsoever.

Homework Equations



n1sinθ1=n2sin2

The Attempt at a Solution



I am lost on this one!
 

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nilic1 said:

Homework Statement



I have a problem with the question in the attachment below. I have no idea on how to proceed as I thought that the ray of light would continue to travel in a straight line with no refraction whatsoever.

Homework Equations



n1sinθ1=n2sin2

The Attempt at a Solution



I am lost on this one!

The angles of incidence and refraction are defined as angles enclosed by the rays and the normal of the interface. Grazing incidence means θ1=90°. What angle does the refracted ray enclose with the normal of the face of cube?

ehild
 
ehild said:
The angles of incidence and refraction are defined as angles enclosed by the rays and the normal of the interface. Grazing incidence means θ1=90°. What angle does the refracted ray enclose with the normal of the face of cube?

ehild

My new attempt is:

n1 sinθ1 = n2sinθ2
1.55 x sin90 = 1.33 x sin θ2
1.55/1.33 = sin θ2
1.165 = sin θ2
∴ something is wrong!
 
The light enters from air. What is n1 then?

ehild
 
n = 1 for air.

so the working changes to

n1 sinθ1 = n2 sinθ2
1 x sin 90 = 1.33 x sinθ2
1/1.33 = sinθ2

θ2 = 48.5 degrees

I am still puzzled ... so when angle i = 90, the medium is air and not glass. If this is so then is the glass cube is irrelevant for the question? If so wouldn't the ray of light go straight and not be bent at the water surface or in the water?

According to the answer in the book the angle in part b ii is 62.9 degrees. Still cannot figure out the path taken by the ray of light. I appreciate your help ehild.
 
ok finally I got it... but my question still is .. Why doesn't the ray continue to travel in a straight line?
 
Last edited:
The ray enters from air onto the surface of the glass cube. That grazing incidence means that it makes an angle a bit less than 90° with the normal, so it really strikes the air/glass surface and enters into the glass, instead going straight into the water. The refracted ray travels inside the glass cube and falls onto the bottom face at a certain angle. Here it is refracted again, from glass into water. Draw the path of the ray and calculate the angles.

ehild
 

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ehild said:
The ray enters from air onto the surface of the glass cube. That grazing incidence means that it makes an angle a bit less than 90° with the normal, so it really strikes the air/glass surface and enters into the glass, instead going straight into the water. The refracted ray travels inside the glass cube and falls onto the bottom face at a certain angle. Here it is refracted again, from glass into water. Draw the path of the ray and calculate the angles.

ehild

So grazing is slightly less than 90 degrees... That explains everything! Thank you so much ehild.
 
You are welcome:smile:

ehild
 
  • #10
ehild said:
The ray enters from air onto the surface of the glass cube. That grazing incidence means that it makes an angle a bit less than 90° with the normal, so it really strikes the air/glass surface and enters into the glass, instead going straight into the water. The refracted ray travels inside the glass cube and falls onto the bottom face at a certain angle. Here it is refracted again, from glass into water. Draw the path of the ray and calculate the angles.

ehild
How do you know from which point the light ray is entering inside the glass cube? Is the pictorial representation of the question
wrong? I mean why isn't the light ray entering first at the upper left corner of the cube ?
 
  • #11
Rongeet Banerjee said:
How do you know from which point the light ray is entering inside the glass cube? Is the pictorial representation of the question
wrong? I mean why isn't the light ray entering first at the upper left corner of the cube ?
The position where the light enters the glass cube is arbitrarily chosen.
 
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