- #1

- 13

- 0

[itex]Ax=\lambda x[/itex]

[itex](A-\lambda )x[/itex] = 0

[itex](A-\lambda I )x[/itex] = 0 -------------------- 1

After the above process we find the determinant of [itex]A-\lambda I [/itex] and then equate it to 0.

det([itex]A-\lambda I [/itex]) = 0 -------------------- 2

Then from the above characteristic equation we find the Eigen values.

My question is how does the equation 1 imply the above condition 2