DLeuPel said:
Would the velocity of a body which is orbiting another body change due to its radius to the center of gravity? If so, why? A body which moves passed a planet and starts orbiting it should have the same velocity it had before ,regarding the fact that it is orbiting a planet. Also, gravity isn’t really a force but the geometrical deformation of the fabric of space time. So really is like if you were riding your car in a tilted road so the car curves itself without the need of any forces acting upon it. The more the gravity the more the road is titled.
To answer the why question directly. Because, the curvature of spacetime outside a spherical object is described by:
##ds^2 = -(1- \frac{2M}{r})dt^2 + (1- \frac{2M}{r})^{-1}dr^2 + r^2(d\theta^2 + \sin^2 \theta d\phi^2)##
Which leads to the "energy" equation of motion:
##E = \frac12(\frac{dr}{d\tau})^2 + V(r)##
Where ##V(r)## is the effective potential. This is the same equation as in Newtonian gravity, but in GR this potential has an additional term. For planetary orbits about the Sun, for example, this additional term is negligible, so we have a valid Newtonian approximation.
You may be thinking (from your rubber sheet or road analogies) that space itself has a defined shape and compels an object to move in a specific physical path. One problem with these analogies is that it is
spacetime that is curved. So, one of the dimensions on your rubber sheet should be the
time dimension, which is not so easy to visualise.
Because spacetime (space and time) are curved, the notion of "constant speed" is not so clear cut. We (as outside observers, using our system of coordinates - centred on the Sun, say) measure a change in coordinate velocity - that is not measurable as an acceleration by the orbiting body itself.