(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

A conical reservoir is 50m deep and 200m across the top. Water is being pumped in at a rate of 7000m^3/min, and at the same time, water is being drained out at a rate of 9000 m^3/min. What is the change in diameter when the height of the water in the reservoir is 20m?

2. Relevant equations

v=(1/3)pi(r^2)(h)

3. The attempt at a solution

h=(.5r)

v=(1/3)(pi)(r^2)(.5r)

=(1/6)(pi)(r^3)

v'=(.5)(pi)(r^2)(r')

7000=.5pi(40^2)(r')

= 2.785

-9000= .5pi(40^2)(r')

=-3.581

2.785-3.581 = -0.796 m/min

my answer, however, is supposed to be -1.6m/min

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# Homework Help: Related rates question conical reservoir

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