Relating escape velocity equations

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Homework Help Overview

The discussion revolves around relating two equations for escape velocity: sqrt(2GM/r) and sqrt(2gr). Participants are exploring the connection between these equations in the context of gravitational force.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the gravitational force equations and attempt to set them equal to each other to derive the relationship between the escape velocity equations. Questions arise about the correct application of these equations and the simplifications involved.

Discussion Status

Some participants are actively engaging with the mathematical relationships and attempting to clarify their understanding of the gravitational force. There is a recognition of a potential math error, and guidance is being offered to help navigate the equations.

Contextual Notes

Participants are working under the constraints of homework rules and are trying to relate concepts learned in different contexts of gravitational force, including both general and surface-level equations.

calfly
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Homework Statement


I'm having a hard time relating the escape velocity equations, sqrt(2GM/r) to sqrt(2gr)

The Attempt at a Solution


I know that both equations mean the same thing, but I can't figure out how to get from the first equation to the second
 
Last edited:
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Do you know the equation for the gravitational force between two objects (in space)?
 
F=-Gm1m2/r^2
 
Yep, and I assume you know the equation for the gravitational force acting on an object on (or near) the surface of the Earth... now, the force should be the same whether you calculate it using one equation or the other. So set the two forces equal to each other and see what you get.
 
err, I think this is where I'm stuck at. if an object is right on the surface of the Earth then I guess the gravitational force would look the same as the general equation-ish
F=-Gm(earth)m(object)/R(earth)^2. I'm not quite sure what I'm looking at when I set them equal to each other.
 
calfly said:
F=-Gm(earth)m(object)/R(earth)^2
OK, well, that's right... now, when I mentioned the equation for gravitational force on an object near the surface of the Earth, I was trying to get you to think of the equation you used before you learned about [itex]F = -Gm_1m_2/r^2[/itex]. Do you remember?
 
Ah I think I'm starting to get it but I'm making a math error somewhere i think,
okay so I set f = mg = -Gm1m/r^2, cancel out "m", --> g=-Gm1/r^2.

now I got to fit that into sqrt(2Gm/R) but that does not get sqrt(2gr)?
err i think.
 
Last edited:
Welcome to PF!

Hi calfly! Welcome to PF! :smile:

(have a square-root: √ and try using the X2 tag just above the Reply box :wink:)
calfly said:
Ah I think I'm starting to get it but I'm making a math error somewhere i think,
okay so I set f = mg = -Gm1m/r^2, cancel out "m", --> g=-Gm1/r^2.

now I got to fit that into sqrt(2Gm/R) but that does not get sqrt(2gr)?
err i think.

( diazona :smile: seems to be offline, so …)

Put g = Gm/r2 into √(2gr). :wink:
 
Just what I was going to say :wink: thanks for jumping in on that, tiny-tim.
 

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