Relation between codifferential and boundary operator

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Discussion Overview

The discussion revolves around the relationship between the codifferential operator (\(\delta\)) and the boundary operator (\(\partial\)), particularly in the context of Stokes' theorem and their roles as adjoints of the exterior derivative. The scope includes theoretical exploration and mathematical reasoning.

Discussion Character

  • Exploratory, Technical explanation, Debate/contested, Mathematical reasoning

Main Points Raised

  • One participant states that the only relation between the codifferential and boundary operator is what is given by Stokes' theorem.
  • Another participant references Stokes' theorem and suggests that a direct formula could be formed between \(\partial\) and \(\delta\) based on their relationships with the exterior derivative and the forms involved.
  • A different participant argues that \(\delta\) and \(\partial\) are fundamentally different concepts and emphasizes that discussing one without the other is nonsensical.
  • Another participant questions the uniqueness of dual objects, implying that the dual of one object does not necessarily lead to a unique dual.

Areas of Agreement / Disagreement

Participants express differing views on the relationship between the codifferential and boundary operator, with some suggesting a connection through Stokes' theorem while others assert their distinctness. The discussion remains unresolved regarding the nature of their relationship.

Contextual Notes

Participants highlight the importance of context when discussing operators, indicating that assumptions about their relationships may depend on specific mathematical frameworks or definitions.

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As we know,the codifferential [tex]\delta[/tex] is the adjoint of the exterior derivative,and the boundary operator [tex]\partial[/tex] is also the adjoint of exterior derivative according to stokes' theorem, then what is the relation between codifferential and boundary operator?
 
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?? The only relation is exactly what you have given: Stoke's theorem.
 
Stokes' theorem states that [tex]<D,d \omega >=<\partial D,\omega>[/tex] ([tex]\partial[/tex] is the boundary operator), exterior derivative d and codifferential [tex]\delta[/tex] hold the relation [tex](\theta ,d \omega)=(\delta \theta ,\omega)[/tex],then could we form a formula between [tex]\partial[/tex] and [tex]\delta[/tex] directly?
 
No, they are completely different things. In fact, it really does not make sense to talk about "d" without the [itex]\omega[/itex] or [itex]\delta[/itex] without the [itex]\theta[/itex].
 
So B=Dual(A) and C=Dual(A) do not imply B=C, right? I once thought that the dual of one object must be unique, it is not true?
 

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