Relation between dB loss and percentage loss

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    Db Loss Relation
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SUMMARY

The relationship between dB loss and percentage loss is defined by specific formulas for power and voltage. For power loss, the formula is 100(1 - 10^(dB/10))%, while for voltage loss, it is 100(1 - 10^(dB/20))%. In both cases, dB values should be negative to represent signal loss. Understanding these calculations is essential for accurately assessing signal strength degradation.

PREREQUISITES
  • Understanding of decibels (dB) as a logarithmic unit
  • Basic knowledge of signal strength and loss concepts
  • Familiarity with power and voltage relationships in electronics
  • Mathematical skills for manipulating exponential equations
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Engineers, telecommunications professionals, and anyone involved in signal processing or electronics who needs to understand the implications of signal loss in dB.

anarachy
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I want to know generally what the relation between dB loss and percentage loss is. If I want to know what percentage of a signals strength is lost knowing what its dB loss is, how would I accomplish that.

Thanks.
 
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For power loss it would be :

100 \left( 1 - 10^{\frac{dB}{10}} \right) \,\%

And for voltage loss it would be :

100 \left( 1 - 10^{\frac{dB}{20}} \right) \,\%Where dB here would be negative for signal loss.
 
Last edited:
Most likely this can only be answered by an "old timer". I am making measurements on an uA709 op amp (metal can). I would like to calculate the frequency rolloff curves (I can measure them). I assume the compensation is via the miller effect. To do the calculations I would need to know the gain of the transistors and the effective resistance seen at the compensation terminals, not including the values I put there. Anyone know those values?

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