Relation between energy annd pressure

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Homework Help Overview

The discussion revolves around the relationship between pressure and energy in the context of gas behavior, particularly focusing on molecular motion and kinetic energy.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants explore the derivation of a relationship between pressure and energy, with references to kinetic energy and gas laws. Questions arise about the starting point and available information for this derivation.

Discussion Status

Some participants have provided insights into relevant equations and concepts, such as the average kinetic energy of gas molecules and the ideal gas law. There is an ongoing exploration of how these concepts relate to the original question, with no explicit consensus reached yet.

Contextual Notes

Participants are discussing various equations that may apply to the relationship between pressure and energy, noting the distinction between molecular and macroscopic perspectives. There is an emphasis on understanding the context in which these equations are valid.

Haseeb Ali
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Me and and my friend were having discussion about the motion of molecules of gas.We talked about their velocity ,kinetic energy and much more. He asked me to derive a relation between pressure and energy. I was unable to explain him that... Can anyone explain the relation?
 
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Haseeb Ali said:
He asked me to derive a relation between pressure and energy.
How would you begin? What information do you have?
 
Bystander said:
How would you begin? What information do you have?
P=density*Vx*2

T= 2/3k 1/2mv*2
 
You could read up on the gas law, e.g. here
Your equations feature in there, but one appears molecular to me and the other macroscopic:

##{1\over 2} mv^2 = {3\over 2} kT## average kinetic energy for a molecule.

##P = \rho v_x^2 = {mass\over V} v_x^2 ## may be ok if in the right context.

I can wrangle a bit with formulas: $$ {1\over 2} mv^2 = {3\over 2} kT\ \Rightarrow\ {1\over 2} mv_x^2 = {1\over 2} kT$$ (the energy is equally distributed over the three degrees of freedom),

##\displaystyle \ \Rightarrow\ v_x^2 = {kT\over m} ##

mass = number of molecules * mass of a molecule = number of moles * ##N_A## * mass of a molecule (Avogadro number); write mass = ##n\; N_A\; m##

Leaves

##pV = n\;N_A\;m \ {kT\over m} = n\; N_A \;kT##;

then use

##R_G = N_A \; k## (gas constant) to get the ideal gas law

##pV = nR_GT##.

pressure times volume has the dimension of energy.

It's not the whole story, but quite a big part of it.
 

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