Relation between system enthelpy and surrounding entropy

Join the discussion
Registration is free. Ask a follow-up in this thread, or start your own.
3 replies · 3K views
mooncrater
Messages
215
Reaction score
18

Homework Statement


It is given in my book that:
ΔStotal=ΔSsystem+ΔSsurrounding
Where S is entropy.
ΔSsurr=-ΔH/T
Therefore:
ΔStotal=ΔSsystem+[-ΔHsystem/T]

As we can see here that ΔSsurrounding=-ΔHsystem/T
is applied here . But is this relation correct?

Homework Equations


ΔS=qreversible/T
Where qreversible is the heat input which is equal to ΔH(enthalpy) for constant P and T.

The Attempt at a Solution


What I think is that , instead of ΔHsystem there should be ΔHsurroundings
Since the change in entropy of surroundings is taken. Am I correct here?
 
Physics news on Phys.org
You you consider system plus the surrounding to be an isolated system and apply conservation of energy, you will find the relation between ΔHsystem and ΔHsurrounding
By the way you are correct here-
mooncrater said:
there should be ΔHsurroundings
And they have not used ΔHsystem instead of ΔHsurrounding They have made use of the energy conservation equation I am talking about.
 
I think the relation you're talking about is
ΔHsystem=-ΔHsurroundings
If energy is taken from the surroundings to the system.
Therefore when:
ΔSsystem=ΔHsystem/T will be equal to minus of ΔHsurroundings
/T
Am I correct here?
 
  • Like
Likes   Reactions: Vatsal Sanjay
Yes you're correct
 
  • Like
Likes   Reactions: mooncrater