1. Limited time only! Sign up for a free 30min personal tutor trial with Chegg Tutors
    Dismiss Notice
Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Entropy: Heat addition to surrounding.

  1. Nov 9, 2012 #1
    If 12007 kJ of heat is lost to the surroundings with an ambient temperature of 25 degrees centigrade during a cooling process, and the ambient temperature of the surroundings is unaffected by the heat addition, what is the entropy change of the surroundings?

    If Δs=∫δQ/T, then Δs=ΔQ/T=12007 kJ/(25+273.15)K= 40.272 kJ/K.

    Is my thinking process here correct?

    Thanks!
     
  2. jcsd
  3. Nov 9, 2012 #2
    Yes.
     
Share this great discussion with others via Reddit, Google+, Twitter, or Facebook




Loading...