Relation of resistance to power dissipation

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SUMMARY

The discussion addresses the relationship between resistance and power dissipation in electrical circuits, specifically through the equations p = i² * R and p = v² / R. It establishes that reducing resistance (R) while keeping voltage (V) constant results in an increase in current (I) according to Ohm's Law. Consequently, the power dissipation increases, demonstrating that a decrease in resistance does not lead to a decrease in thermal energy but rather a significant increase in power dissipation, quantified by a factor of 2 in this scenario.

PREREQUISITES
  • Understanding of Ohm's Law
  • Familiarity with electrical power equations
  • Basic knowledge of thermal energy concepts in resistors
  • Ability to manipulate algebraic equations
NEXT STEPS
  • Study the implications of Ohm's Law in circuit design
  • Explore thermal management techniques in resistive components
  • Investigate the effects of varying voltage and resistance on power dissipation
  • Learn about advanced power analysis tools for electrical circuits
USEFUL FOR

Electrical engineers, physics students, and anyone involved in circuit design or analysis will benefit from this discussion, particularly those focusing on power dissipation and thermal management in resistive components.

omari_yousef
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Equation (p=i^2 * R) seems to suggest that the rate of increase of thermal energy in a resistor is reduced if the resistance is made less.

"Eq" : p =v^2/R seems to suggest just the apposite .

How do you reconcile this apparent paradox?
 
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omari_yousef said:
Equation (p=i^2 * R) seems to suggest that the rate of increase of thermal energy in a resistor is reduced if the resistance is made less.

"Eq" : p =v^2/R seems to suggest just the apposite .

How do you reconcile this apparent paradox?

You reconcile it by noticing that, if V is constant, then you cannot reduce R without increasing I (ohm's law). If you reduce R by a factor of 2, then you increase I by a factor of 2, which means that, using the first equation, your power changes by a factor of (2^2)/2 = 4/2 = 2.

Using the second equation, your power changes by a factor of 1/(1/2) = 2.
 

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