Hello,(adsbygoogle = window.adsbygoogle || []).push({});

it is possible to prove that the Mellin transform of a functionf(x)can be expressed in terms of Fourier transform, namely:

[tex]\mathcal{M}\{f(x)\}(s) = \mathcal{F}\{f(e^{-x}\}(-is)[/tex]

I am not convinced of that imaginary unitias argument of the Fourier transform. In fact, since the argument (-is) is imaginary, that is not a Fourier transform anymore.

I don't see I could compute a Mellin transform using a Fourier transform. Am I missing something?

**Physics Forums - The Fusion of Science and Community**

The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

# Relationship between Fourier and Mellin transforms

Loading...

Similar Threads - Relationship between Fourier | Date |
---|---|

I Showing relationship between zeta and gamma | Feb 26, 2018 |

What exactly is the relationship between calculus and differential equ | Mar 23, 2014 |

Relationship between division, subtraction, and limits | Sep 24, 2013 |

Relationship between trace and phase space | Jun 18, 2013 |

Relationship between Derivatives and Integrals | Apr 3, 2013 |

**Physics Forums - The Fusion of Science and Community**