Ace.
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Homework Statement
We calculated times of the periods of varying pendulum lengths. (20cm, 40cm, 60cm, 80cm). Then the frequency was calculated for each length and then a frequency-length graph was made. Since the graph is an exponential relationship we graphed our values on a log-log chart. Then we found the equation y = kxn, where k is the value of y where x = 1, and n is the slope.
the following equation was found from the log-log chart, wehre f is the frequency and L is the length:
f = 1.5L^{-0.5}
What is the equation that relates frequency to length in a pendulum?
Homework Equations
T = 2\pi\sqrt{\frac{L}{g}}
f = 1.5L^{-0.5}
The Attempt at a Solution
I can come up with the equation for f from using the first equation
\frac{1}{f} = 2\pi\sqrt{\frac{L}{g}}
f = \frac{1}{2\pi\sqrt{\frac{L}{g}}}
But my issue is does the equation I found for my log-log chart (f = 1.5L^{-0.5}) play any role in finding the relationship? What is the significance of this equation? Would there be a way to derive f = \frac{1}{2\pi\sqrt{\frac{L}{g}}} using it?