Relative Velocities: Plane vs Air & Ground

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Homework Help Overview

The discussion revolves around a problem involving relative velocities, specifically focusing on a small plane flying over a runway while affected by a crosswind. The participants are analyzing the plane's speed with respect to the air and ground, considering the wind's influence on the plane's trajectory.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants discuss the setup of the velocity equation and the vector nature of the problem. There are attempts to clarify the relationship between the plane's speed, the wind speed, and the resultant velocity. Questions arise regarding the use of the square root in the calculations and the interpretation of the wind's direction.

Discussion Status

The discussion is active, with participants questioning each other's reasoning and clarifying concepts related to vector addition. Some guidance is offered regarding the use of vector diagrams to visualize the problem. There is no explicit consensus on the correct speed of the plane with respect to the air.

Contextual Notes

Participants note confusion regarding terminology, particularly the use of "crosswise" versus "perpendicular," which affects their understanding of the problem setup. The original poster's calculations yield a result that does not match the provided options, leading to further exploration of assumptions and definitions.

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Homework Statement



A small plane flies at 120km/h over the end of a runway along the axis of the runway. There is a crosswind, exactly 90 degrees to the direction of the runway, blowing at 50km/h. The speed of the plane with respect to the air is:

130km/h
50km/h
120km/h
need more info
70km/h

Homework Equations





The Attempt at a Solution



I set up the equation:

V(p/g) ( plane respect to ground ) = V(p/a) (plane respect to air) + V(a/g) (air respect to ground)

p/g = 120 a/g =50

120 = 50 +x
sqrt(120^2 - 50^2) = x ?

this gives 109 km/h though which is not a choice, did I do something wrong?
 
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sqrt(120^2 - 50^2)
Why this?

The plane is flying straight with the runway at 120 mph, and the plane has to be moving through the air. The wind is blowing cross-wise so the planes velocity in the air must be the vector sum of its velocity and the winds velocity.
 
Why are you taking the square root? Everything is in the same direction.
 
how is everything in the same direction if the wind is blowing perpindicular to the runway
 
so it is 130?

the reason i was subtracting was because I tried putting it into the equation

V p/a = V p/b + V b/a

and i got

120 = x + 50
 
Oh, I guess I don't know what crosswise means. I thought it meant across the cross section. Why not just say perpendicular, or if they really want to be fancy, orthogonal. I guess I am still an idiot for not even reading the 90 degree part, my bad. Yes, it would be 130.

Do the vector diagram, and it should be pretty apparent.
 

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