# Relativistic momentum (Lorentz boost) low velocity limit

1. Nov 17, 2015

### Neutrinos02

Hello,

If I have a momenta pμ=(E,px,py,pz) and transform it via lorentz boost in x-direction with velocity v I'll get for the new 0th component E′=γE+γvpx why is this in the limit of low velocities the same as transforming the energy by a galilei transformation with velocity v? For γvpx i get something like vpx+O(v³) and with a galilei transformation I'll have terms (with px=mu) like 1/2m(u−v)²=1/2mu²−vpx+1/2mv². So in the relativistic case I got the wrong sing for vpx+O(v³)and lost the 1/2mv²? Did I make a mistake?

Thanks for help
Neutrinos

2. Nov 17, 2015

### PAllen

For the sign error, if if you have (u-v) in the Galilean case, you need E′=γE-γvpx for the corresponding relativistic case. The rest is just algebra, but I am not disposed to work it out right now.