Relativity Problem: Find Passenger Speed Relative to Bank

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SUMMARY

The discussion centers on calculating the speed of a passenger relative to the bank while on a ferry boat moving away from the bank. The ferry travels at 3 km/h, the river flows at 4 km/h, and the passenger walks at 1.39 m/s at an angle of 53.1 degrees upstream. The initial approach involved using Lorentz transformations, but it was concluded that the problem can be solved using basic vector addition due to the low speeds involved, making relativity irrelevant.

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Homework Statement



A ferry boat headed directly away from the river bank is traveling at 3 km/h with respect to the water in a river flowing at 4 km/h. A passenger walks diagonally toward the stern of the boat with a speed of 1.39 m/s. The passenger's path is at an angle of 53.1 degrees toward the upstream direction from the length of the boat. What is the passenger's speed relative to the bank?

Homework Equations



v'=(u+v)/(1+(u*v)/c^2)

The Attempt at a Solution



I know the speeds form a triangle with leg lengths 3 and 4 and hypotenuse 5. I'm not sure where to go from there, though...
 
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It looks like you might have to use 2 lorentz transformations. First, i would set up my rest frame, S, to be the water, and the moving S' frame to be the boat. I would then find the velocity of the person in the reference frame of the water, S. I would then use the lorentz transformations again, setting my new rest frame to be the bank and my moving frame to be the water. This way you willk now the velocity of the person relative of the water and will be able to transform it to the bank. this might be wrong though -- my spec rel is not great.
 
bfr said:
… 3 km/h … 4 km/h … 1.39 m/s …

Hi bfr! :smile:

erm … are you sure this is a relativity question? :confused:

The speeds are far too small for relativity to be relevant … I think you're expected to treat it as a straightforward vector addition problem. :smile:
 

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