Relativity Question: Airliner -- Light & ball movement

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Homework Help Overview

The discussion revolves around a problem in relativity involving the motion of a ball and a beam of light from the perspective of an observer on Earth while on an airliner traveling at a constant speed. The original poster explores how these two entities would appear to move relative to the Earth's frame of reference and questions the effects of time dilation on their watch.

Discussion Character

  • Exploratory, Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • The original poster attempts to calculate the velocities of the ball and light from the Earth's frame of reference, discussing the principles of vector subtraction and the constancy of the speed of light. They also raise questions about the implications of time dilation based on the speed of the airplane.

Discussion Status

Participants are engaging in clarifying the concepts of inertial frames, relativistic velocity addition, and the implications of time dilation. Some express uncertainty about their understanding and seek confirmation on their reasoning, while others provide insights into the necessity of using relativistic formulas for accuracy.

Contextual Notes

There is mention of a lack of prior instruction on certain concepts such as inertial/non-inertial frames and relativistic velocity addition, which may affect the participants' understanding of the problem.

Jaimie
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Homework Statement


Imagine that you are flying on an airliner on a long flight to Europe at a constant speed of 300 m/s

a) you throw a ball towards the back of the plane at 20 m/s. You then shine a beam of light towards the back of the plane. How will these two things i) the ball and ii) the light-- appear to move from the Earth's frame of reference

b) would you expect your watch to be affected by time dilation?

Homework Equations


Δtm = Δts/√(1-v2/c2)
V(be)= -V(bp) + V(pe)

The Attempt at a Solution


a) i) b= ball; e= earth; p= plane
∴ V(be)= -V(bp) + V(pe)= -20 m/s + 300 m/s = 280 m/s [forward].

ii) The light will remain at a constant 3.0 x 10^8 m/s from the earth’s frame of reference.

Velocity is dependent on its’ inertial reference frame and its’ direction of travel. From the Earth frame of reference, both the direction of the thrown ball and the direction of the airplane travel determines its’ velocity as per vector subtraction. If we were to look at the ball moving from a different inertial frame of reference (i.e. from the plane), the ball would experience only the velocity of 20m/s [backwards] and if the ball was thrown forward, the velocity of the ball would be 20 m/s + 300 m/s= 320 m/s [forward]. Light on the other hand is independent of its’ reference frame and shows a constancy of 3.0 x 10^8 m/s relative to all inertial reference frames (special relativity postulate 2), regardless of which direction it is travelling. If we were to measure the speed of light from inside the plane or if it were traveling back or forwards, its’ velocity would still be 3.0 x 10^ 8 m/s.

b) If time was being measured from the earth’s frame of reference, time dilation would still occur relative to the time experienced from the airplane. However, because the plane is not traveling at a speed close enough to the speed of light, increasing the time difference between both reference frames, time difference and time dilation would be negligible. As such, my watch would not be accurate enough to pick up the time difference. If time was measured from the inside the plane, my watch would only experience normal time and would not experience time dilation at all.

Could someone review my answers and tell me if I am understanding these concepts?
Thank you for your time!
 
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Jaimie said:
∴ V(be)= -V(bp) + V(pe)= -20 m/s + 300 m/s = 280 m/s [forward].
As this is a relativity question, I would use the relativistic formula and sufficient precision to see the difference to the nonrelativistic case.
Jaimie said:
ii) The light will remain at a constant 3.0 x 10^8 m/s from the earth’s frame of reference.
Sure.
Jaimie said:
b) If time was being measured from the earth’s frame of reference, time dilation would still occur relative to the time experienced from the airplane. However, because the plane is not traveling at a speed close enough to the speed of light, increasing the time difference between both reference frames, time difference and time dilation would be negligible. As such, my watch would not be accurate enough to pick up the time difference. If time was measured from the inside the plane, my watch would only experience normal time and would not experience time dilation at all.
Right. There are watches precise enough to note the time dilation, however.
 
Hi mfb,
Re a) i & ii) :
At this point we weren't taught about inertial/non-inertial frames of reference, time dilation and simultaneity, with no other equations other than that for time dilation. So based on this info, are both these answers correct? Thank you!

(I'm curious though, which equation(s) were you referring to?)
 
Should be fine.

Relativistic velocity addition.
You need a modified formula in relativity - this becomes more easy to see if your ball moves with (speed of light minus 10m/s) forwards in the plane, for example. The classical addition would give a speed above the speed of light, which is obviously wrong. The correct relativistic formula also allows to plug in the speed of light, and the result is the speed of light again as expected.
 
*Correction*
"At this point we were taught only about inertial/non-inertial frames of reference, time dilation and simultaneity..." Had to fix that in my last post.

So when you're saying "should be fine", you're saying that based on what I learned, my answer to part a i) is correct? I just wanted to clarify.

Interesting. I wish we would have learned about this as this makes more sense based on your explanation.
Thank you for your help!
 
Jaimie said:
So when you're saying "should be fine", you're saying that based on what I learned, my answer to part a i) is correct? I just wanted to clarify.
I'm not in your course, but if you did not learn relativistic velocity addition yet, it is fine.
 
Great! Thank you for your help.
 

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