Relearning differential equations,

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SUMMARY

The discussion focuses on solving the differential equation d^4x/dx^4 - d^2x/dx^2 + a = 0, where 'a' is a parameter. Participants clarify that 'a' should be treated as a fixed parameter that can yield different solutions based on its value. A suggested approach involves transforming the equation into a simpler form by letting y = d^2x/dt^2, leading to the equation d^2y/dt^2 - y + a = 0. This transformation allows for a clearer understanding of how varying 'a' affects the solutions.

PREREQUISITES
  • Understanding of differential equations, specifically fourth-order and second-order equations.
  • Familiarity with parameterized equations and their implications in solutions.
  • Knowledge of transformation techniques in differential equations.
  • Basic calculus, particularly derivatives and their applications in physics.
NEXT STEPS
  • Study the method of solving fourth-order differential equations.
  • Learn about parameter variation in differential equations and its impact on solutions.
  • Explore transformation techniques for simplifying complex differential equations.
  • Investigate the applications of differential equations in physics, particularly in mechanics.
USEFUL FOR

Students in physics and mathematics, particularly those tackling differential equations in their coursework or research. This discussion is beneficial for anyone seeking to deepen their understanding of parameterized differential equations and their solutions.

Daniel Sellers
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Homework Statement


I was never great in diffEQ, but now I have to solve this problem for physics homework and I'm pretty lost.

d^4x/dx^4 - d^2x/dx^2 + a =0

Where a is a parameter.

Homework Equations

The Attempt at a Solution


I have tried solutions like e^kt which work accept for the parameter a. The problem asks specifically what happens if a varies, so I can't even treat it like a constant
 
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Daniel Sellers said:

Homework Statement


I was never great in diffEQ, but now I have to solve this problem for physics homework and I'm pretty lost.

d^4x/dx^4 - d^2x/dx^2 + a =0

Where a is a parameter.

Homework Equations

The Attempt at a Solution


I have tried solutions like e^kt which work accept for the parameter a. The problem asks specifically what happens if a varies, so I can't even treat it like a constant

I assume you mean ##d^4 x/dt^4##, etc; otherwise your DE makes no sense at all!

I suspect they mean that ##a## is a "parameter" that is fixed throughout a solution, but that different values of ##a## can give you different solutions. At least, that is how I read it. Otherwise, the problem should have written ##a(t)## instead of just plain ##a##.

Anyway, if ##a## really is a constant, the function ##y = d^2 x/dt^2## satisfies ##d^2 y /dt^2 - y + a = 0##, so ##z = y-a## satisfies ##d^2 z /dt^2 - z = 0.##
 
Yes, there are t's in the denominator. Tha ks so much, I think that will work!
 

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