Required change in pressure to change volume

[ryan.howie]

Homework Statement

How much pressure is needed to compress the volume of an iron block by 0.10%?

Homework Equations

the bulk modulus of iron= 9*10^10
delta_P= B*Vo/delta_V

The Attempt at a Solution

I have tried using random volume for example 1 and 0.01, and 2 and 0.02 but i feel i am way off.

 

[LowlyPion]

Homework Statement

How much pressure is needed to compress the volume of an iron block by 0.10%?

Homework Equations

the bulk modulus of iron= 9*10^10
delta_P= B*Vo/delta_V

The Attempt at a Solution

I have tried using random volume for example 1 and 0.01, and 2 and 0.02 but i feel i am way off.

Welcome to PF.

Why do you feel you are way off?

Note though that B = ΔP/(ΔV/V)

http://hyperphysics.phy-astr.gsu.edu/hbase/permot3.html#c1

They give you already that ΔV/V = .1%

 

[ryan.howie]

Thanks for the welcome and quick reply,

so ΔP=B(ΔV/V)
and B=9*10^10
and as you said ΔV/V=1%
so the change in pressure should be 1% of B which 9*10^8 N/m^2
but this is one of my previous answers and is wrong.

 

[LowlyPion]

Thanks for the welcome and quick reply,

so ΔP=B(ΔV/V)
and B=9*10^10
and as you said ΔV/V=1%
so the change in pressure should be 1% of B which 9*10^8 N/m^2
but this is one of my previous answers and is wrong.

Reread the problem statement, and my statement again.

How much pressure is needed to compress the volume of an iron block by 0.10%?

They give you already that ΔV/V = .1%

 

[ryan.howie]

Sorry that was a stupid mistake. The pressure needed should be 9*10^7. thanks you for your help

 

[LowlyPion]

Sorry that was a stupid mistake. The pressure needed should be 9*10^7. thanks you for your help

Let's be more generous and call it careless.

As they say:

Careless happens.