Required force to stop a moving object.

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SUMMARY

The discussion centers on calculating the force required to stop a 6 kg object moving at a constant speed of 10 m/s over a period of 30 seconds. The user applied Newton's second law, concluding that the force exerted by the man is 2 N, derived from the equation F = m*v(0)/t. An alternative method suggested is the impulse-momentum theorem, which may simplify the calculation process. The solution is confirmed to be correct, but the importance of including units in calculations is emphasized.

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Homework Statement


A solid object of 6kg was moving at a constant speed of 10m/s towards a man who try to stop it.
If the man stopped the train in 30 seconds, find the force F that the man exerted on the object.


The Attempt at a Solution


The only force acting on the object is the man's force so : ma=-F, this means that : v(t)=v(0)-F t /m.
We know that v(30)=0, which means that : F= m*v(0)/30 = 2.

Is my solution correct ? (I don't have anyone to ask him so I'm asking you).
 
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aziiri said:

Homework Statement


A solid object of 6kg was moving at a constant speed of 10m/s towards a man who try to stop it.
If the man stopped the train in 30 seconds, find the force F that the man exerted on the object.

The Attempt at a Solution


The only force acting on the object is the man's force so : ma=-F, this means that : v(t)=v(0)-F t /m.
We know that v(30)=0, which means that : F= m*v(0)/30 = 2.

Is my solution correct ? (I don't have anyone to ask him so I'm asking you).

Seems fine, but put in units.
 
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An alternative (and easier) way of doing this is to use the impulse-momentum theorem.
 

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