Residue Theorem: Show r1+r2 = Res(f1+f2, z0)

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SUMMARY

The discussion centers on proving that the residue of the sum of two functions, f1 and f2, at a point z0 is equal to the sum of their individual residues, r1 and r2. The residue is calculated using the limit formula Res(f, z0) = lim(z→z0) (z-z0)f(z). The proof confirms that Res(f1 + f2, z0) = Res(f1, z0) + Res(f2, z0) = r1 + r2, demonstrating the additive property of residues in complex analysis. The concept of residues is tied to the existence of poles and the expansion of functions into Laurent series.

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  • Knowledge of limits and continuity in mathematical functions
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Students and professionals in mathematics, particularly those studying complex analysis, as well as educators teaching the residue theorem and its applications in calculus and mathematical analysis.

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Homework Statement



If f1 and f2 have residues r1 and r2 at z0. show that the residue of f1+ f2 is r1 + r2

The Attempt at a Solution



Res(f1, z0) = limz-->z0 (z-z0)f1(z) = r1
Res(f2, z0) = limz-->z0 (z-z0)f2(z) = r2

now calculate Res(f1+f2, z0)

=

limz-->z0 (z-z0)(f1(z)+ f2(z))
= limz-->z0 (z-z0)(f1(z))+(z-z0)(f2(z) = r1+ r2

Is it really this easy? i must be doing something wrong
 
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Pretty much, yeah. "Residue" is only defined for poles and a function has a pole at [itex]z_0[/itex] if and only if it can be expanded in a power series (a Laurent series) with a finite number of negative exponents. In that case the residue is the coefficient of z-1 (thus that limit formula you use). Adding the two functions, you can add the Laurent series term by term: [itex]a_1z^{-1}+ a_2z^{-2}= (a_1+ a_2)z^{-1}[/itex]. The residues add.
 
Thanks halls.
 

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