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Resistance In Series/Parallel circuits

  1. Oct 27, 2014 #1
    1. The problem statement, all variables and given/known data
    Hi, I need to find the total resistance of a circuit (attached file). I'm pretty sure it's really and straight forward but I'm a chemical engineer and this is coursework so just wanted to make sure I was doing it right.

    2. Relevant equations


    3. The attempt at a solution
    Do I just simplify by adding the following to each other in series to give three resistor value (R2+R3) (R4+R5+R6) (R7+R8) then work it out using these in the parallel question? ie Rcircuit= R1 + R9 + [(1/Rtotal)=1/(R2+R3) + 1/(R4+R5+R6)] + 1/(R7+R8)]


    I totally appreciate they way I have just typed this was not very clear so I'm happy to explain myself more!

    *Edited*
     

    Attached Files:

  2. jcsd
  3. Oct 27, 2014 #2

    haruspex

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    That cannot be right because R4 is not parallel to R7 and R8. But you have the right approach - collapse combinations in stages, starting with the simplest ones.
     
  4. Oct 27, 2014 #3
    So do I add R1 + R4 + R9 in series. Then do the parallel calculation [(1/Rtotal)=1/(R2+R3) + 1/(R5+R6)] + 1/(R7+R8)]? Sorry not done physics in 3 years so I'm a bit rusty!
     
  5. Oct 27, 2014 #4
    Is this what I do anyone?
     
  6. Oct 27, 2014 #5

    haruspex

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    Not R4. There's a connection with other resistors in between R1 and R4.
    In general, you look for:
    - two resistors in sequence with no other connection between them; if found, combine them, adding resistances
    - two resistors joined to each other at both ends; if found, combine them using the parallel resistance rule
    - repeat as necessary
    Yes, you can combine 2 with 3, 5 with 6, and 7 with 8. What next?
     
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