Resistance of A to B in Current Electricity Homework

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Homework Help Overview

The discussion revolves around finding the resistance between points A and B in a circuit diagram related to current electricity. Participants are exploring the configuration of resistors and their arrangement, including concepts such as series and parallel circuits.

Discussion Character

  • Exploratory, Conceptual clarification, Problem interpretation, Assumption checking

Approaches and Questions Raised

  • Participants suggest various methods to simplify the circuit, including unfolding the diagram and considering symmetry. There are discussions about the implications of adding a voltage source and the characteristics of a Wheatstone bridge. Questions arise about combining resistances and the overall current drawn.

Discussion Status

There is active engagement with multiple interpretations of the circuit's configuration. Some participants have offered guidance on how to approach the problem, while others are still grappling with the complexities of the setup. The discussion is ongoing, with no explicit consensus reached yet.

Contextual Notes

Participants note that all resistors have the same value, which may influence the approach to the problem. There is also mention of a potential need for a Kirchhoff analysis, indicating the complexity of the circuit.

1/2"
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Homework Statement


Find the resistance between the A and B( image attached)

Homework Equations


The Attempt at a Solution


I could only simplify the diagram to this (2 attached pic) and i can't proceed any further since i can't identy find any parallel or series circuit/
 

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You can unfold the first picture ... put points A and B in the corners, then unfold the triangle point A is on so A is outside the big triangle. See how to simplify it now?
No? Imagine a voltage source VAB between A and B and you have to find the total current drawn ... now do you get it?

You end up with the resistors forming an H ...
 
Last edited:
If you redraw it slightly differently you will see that by symetry one R has no voltage across it. So it can be removed without effecting the circuit. Makes it much easier to simplify further.
 
Simon Bridge said:
You can unfold the first picture ... put points A and B in the corners, then unfold the triangle point A is on so A is outside the big triangle. See how to simplify it now?
No? Imagine a voltage source VAB between A and B and you have to find the total current drawn ... now do you get it?

You end up with the resistors forming an H ...
resistance in between the parallel line of H... how do i combine it with others??:cry:
(Thanks A LOT for answering!:smile:)
 
1/2" said:
resistance in between the parallel line of H... how do i combine it with others??:cry:
(Thanks A LOT for answering!:smile:)

If you see carefully, there's a wheat stone bridge.
 
Pranav-Arora is correct - it's a Wheatstone bridge. How does one of those work?

You may understand it better if you add a DC voltage source to the diagram between A and B ... one of the resistors in the H does not carry a current: so you can just replace it with an open circuit.

If you still don't see it - use Kirkhoffs rules to find the relationship between VAB and the total current drawn, then Ohm's Law gets you the rest of the way.
 
sorry-deleting my post
 
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@aziziwi: I'd have let 1/2" explore the situation in terms of existing knowledge more before introducing new ideas.

Since all the resistors have the same value, there is no need for the Y-Δ transform. Not that it isn't cool to know...

1/2" is about to discover that the problem only looks complicated. Worst case now is that he does a 3-loop/4-node Kirkhoff analysis ... which is lots of work, but sometimes you have to do something the long way before you realize where the shortcut is. Builds character ;)

I think we've gone as close as we can to actually doing the problem ... let's wait for 1/2" to get back to us.
 

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