- #1

godiswatching_

- 12

- 1

- Homework Statement
- Homework statement in the image.

- Relevant Equations
- $$R=\rho\frac{l}{A}$$

$$l=2\pi r$$

Hey! I had a question about this problem.

I did (1) Using

$$R_{0}=\rho\frac{l}{A}$$

For (2) I assume the question means that the radius increases by a meter.

So I used $$\bigtriangleup L = 2\pi (r_{E}+1) - l$$

and then I used that L to find the new R. Then I said $$\bigtriangleup R = R-R_{0}$$

Does that seem right? This seems too simple to be right.

My final answer was:

$$\bigtriangleup R = 3.4 \cdot 10^{-4} \Omega$$

I did (1) Using

$$R_{0}=\rho\frac{l}{A}$$

For (2) I assume the question means that the radius increases by a meter.

So I used $$\bigtriangleup L = 2\pi (r_{E}+1) - l$$

and then I used that L to find the new R. Then I said $$\bigtriangleup R = R-R_{0}$$

Does that seem right? This seems too simple to be right.

My final answer was:

$$\bigtriangleup R = 3.4 \cdot 10^{-4} \Omega$$