- #1

Samama Fahim

- 52

- 4

How would we calculate the Thevenin's resistance for the above circuit? The right answer for this circuit is 1.5 kOhm.

$$R_{567} = R_7 + (R_5 \parallel R_6) = .5 + .67 = 1.2 k\Omega$$

$$R_{34567} = R_3 + (R_4 \parallel R_{567}) = 1 + .75 = 1.75 k\Omega$$

$$R_{TH} = R_1 + (R_2 \parallel R_{34567}) = 2 + .93 = 2.93 k\Omega,$$

which is not the right answer. Where am I making the mistake?

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