Resistance of the insulation in coaxial cable

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SUMMARY

The resistance of the insulation in a coaxial cable can be calculated using the formula R = ρ(l/A), where ρ is the resistivity, l is the length of the cable, and A is the cross-sectional area between the inner radius 'a' and outer radius 'b'. The area A is determined by the equation A = π(b² - a²). However, for accurate results, integration may be necessary due to the varying area with respect to radius. This approach ensures a precise calculation of resistance across the insulation material.

PREREQUISITES
  • Understanding of electrical resistance and resistivity
  • Familiarity with coaxial cable structure
  • Knowledge of calculus for integration
  • Basic geometry for area calculation
NEXT STEPS
  • Study the principles of coaxial cable design and its electrical properties
  • Learn about the integration techniques for varying cross-sectional areas
  • Explore the impact of material resistivity on insulation resistance
  • Review examples of resistance calculations in cylindrical geometries
USEFUL FOR

Electrical engineers, physics students, and anyone involved in the design or analysis of coaxial cables and their insulation properties.

rupesh57272
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Homework Statement


Determine the resistance of the insulation in a length l of coaxial cable.inner radius = a and outer radius= b.

Homework Equations



R=\rho\frac{l}{A}
Area= \pi (b^2 - a^2)

The Attempt at a Solution


I calculated the area between the two concentric 'circle' with radius 'a' and 'b'.

Then I calculated R using the formula.

However I am not sure whether it is correct approach or not
 
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rupesh57272 said:

Homework Statement


Determine the resistance of the insulation in a length l of coaxial cable.inner radius = a and outer radius= b.


Homework Equations



R=\rho\frac{l}{A}
Area= \pi (b^2 - a^2)

The Attempt at a Solution


I calculated the area between the two concentric 'circle' with radius 'a' and 'b'.

Then I calculated R using the formula.

However I am not sure whether it is correct approach or not

I believe you will need to do an integration instead. The value of A is changing with radius...
 
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