Resistivity and Ohm's Law question

[Vickyvicksss]

Homework Statement

A long wire connected to the terminals of a 12V battery has 6.4 x 10¹⁹ electrons passing a cross section of wire each second. calculate it's resistance.

answer is 1.2Ω

Homework Equations

q = ne
q = IE
R=ρ L/A

The Attempt at a Solution

V= 12v
n= 6.4 x 10¹⁹ electrons
R=?

First I used the number of electrons to find my charge (q)
q = ne
q = (6.4 x 10¹⁹) ( 9 x 10^-31)
q = 5.76 x 10 ^-11

Then calculating my current
I= Q/T
Im assuming T is 1s, because it says "passing a cross section of wire each second"
I = 5.76 x 10 ^-11/ 1
I= 5.76 x 10 ^-11

Then i calculated my resistance
R= V/R
R= 12/5.76 x 10 ^-11
R= 2.0 x 10¹¹

What am i doing wrong? D:

 

[rock.freak667]

The charge of an electron is e=1.6(10^-19) C.

 

[Simon Bridge]

q = ne
q = (6.4 x 1019) ( 9 x 10-31[/color])

... that would be the electron mass.

e=1.60217646×10^-19 Coulombs

 

[Vickyvicksss]

The charge of an electron is e=1.6(10^-19) C.

... that would be the electron mass.

e=1.60217646×10^-19 Coulombs

LOL! CRAP! i knew that~ :) Thank you :3 I was going insane for a bit.

 

[Simon Bridge]

Happens to the best of us :-)