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## Homework Statement

A long wire connected to the terminals of a 12V battery has 6.4 x 10

^{19}electrons passing a cross section of wire each second. calculate it's resistance.

answer is 1.2Ω

## Homework Equations

q = ne

q = IE

R=ρ L/A

## The Attempt at a Solution

V= 12v

n= 6.4 x 10

^{19}electrons

R=?

First I used the number of electrons to find my charge (q)

q = ne

q = (6.4 x 10

^{19}) ( 9 x 10

^{-31)}

q = 5.76 x 10

^{-11}

Then calculating my current

I= Q/T

Im assuming T is 1s, because it says "passing a cross section of wire each second"

I = 5.76 x 10

^{-11}/ 1

I= 5.76 x 10

^{-11}

Then i calculated my resistance

R= V/R

R= 12/5.76 x 10

^{-11}

R= 2.0 x 10

^{11}

What am i doing wrong? D: