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Vickyvicksss
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Homework Statement
A long wire connected to the terminals of a 12V battery has 6.4 x 1019 electrons passing a cross section of wire each second. calculate it's resistance.
answer is 1.2Ω
Homework Equations
q = ne
q = IE
R=ρ L/A
The Attempt at a Solution
V= 12v
n= 6.4 x 1019 electrons
R=?
First I used the number of electrons to find my charge (q)
q = ne
q = (6.4 x 1019) ( 9 x 10-31)
q = 5.76 x 10 -11
Then calculating my current
I= Q/T
Im assuming T is 1s, because it says "passing a cross section of wire each second"
I = 5.76 x 10 -11/ 1
I= 5.76 x 10 -11
Then i calculated my resistance
R= V/R
R= 12/5.76 x 10 -11
R= 2.0 x 1011
What am i doing wrong? D: