Resistivity of a material involving temp

Click For Summary

Homework Help Overview

The discussion revolves around determining the coefficients α and β in the resistivity equation of a material as a function of temperature. The original poster presents a specific equation relating resistivity to temperature and seeks assistance in finding these coefficients based on given temperature and resistivity values.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the form of the resistivity equation and its implications for finding α and β. Some express confusion about the equation's structure and how to derive the coefficients from the provided data. Others suggest setting up linear equations based on the resistivity values at different temperatures.

Discussion Status

There is an ongoing exploration of the correct approach to solve for α and β, with some participants offering guidance on how to set up equations based on the provided resistivity values. The original poster expresses confusion and seeks clarification, indicating that the discussion is still active without a clear consensus on the method to be used.

Contextual Notes

Participants are working under the constraints of the original equation provided by the poster, which they are attempting to analyze despite differing interpretations of its form. There is also mention of expected values for α in various metals, which may influence the discussion.

Felicitymaroon
Messages
4
Reaction score
0

Homework Statement


A) To= 35 °C find α And β
B) determine the temp in which this material becomes a super conductor as predicted by the equation below.
ρ=ρ0(1 + α(T-To) + β(T-To)^2)To= 35 C. ρo=2.5e-8Ω m
T1= 0 C. ρ1=2.346e-8Ω m
T2= 100 C. ρ2=3.036e-8Ω m

Homework Equations


ρ=ρ0(1 + α(T-To) + β(T-To)^2)

The Attempt at a Solution


I'm not sure how to find beta or if there's an equation for it. I tried plugging in the information in the equation using To=35 C and T= 100 C . Please help. I'm lost!
 
Last edited:
Physics news on Phys.org
Where did this question come from? I know this type of question but I have never seen the equation written in this form.
I think the equation you have been given should (!) be
ρt = ρ0(1 + αt + βt^2)
where ρt is the resistivity at a temp tC
ρ0 = resistivity at 0C (2.5e-8)

If you use the information in the equation I have given you will get 2 equations from which you can determine α and β
I hope this helps you get further.
Have a go then contact me and I will tell you what values I got.
 
Last edited:
nope. the equation i originally posted is the correct one. Can you help me solve that one? I am pretty confused.
 
OK... I'll go through it again and get some answers for α and β.
I will let you know
 
Felicitymaroon said:
I'm not sure how to find beta or if there's an equation for it. I tried plugging in the information in the equation using To=35 C and T= 100 C .
Plugging the data given into the given generic equation should give you two linear equations in the two unknowns. In one equation you set T = T1, ρ = ρ1, in the other set T=T2 etc. T0, ρ0 are the same in both.
 
Using the values I listed in #2 I got α = 1.3 x 10^-3 and β = 1.65 x 10^-5

The value of α for aluminium = 3.8 x 10^-3
for brass σ = 1.5 x 10^-3 and for copper σ = 4.3 x 10^-3

Predicting the temp at which superconductivity occurs means pre3dicting the temperature when ρ0
would become zero.
This is essentially 1/α for metals. so in this example the temp would be -769C !
Doing the same for the other metals gives temperatures of aluminium -263
brass -666 and copper -230

Hope this helps (do you know what answers you are expected to get?)
 

Similar threads

  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 1 ·
Replies
1
Views
3K
Replies
2
Views
2K
  • · Replies 2 ·
Replies
2
Views
1K
  • · Replies 9 ·
Replies
9
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
Replies
6
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 6 ·
Replies
6
Views
3K