Resolving Forces in 3D - Statics

Click For Summary
SUMMARY

The discussion focuses on resolving forces in a 3D statics problem involving a pole supported by three guy wires. The resultant force R is 1000-N, with known forces F2 and F3 at 400-N and 500-N, respectively. Participants emphasize the importance of correctly applying the equilibrium equations, particularly the summation of forces equating to zero. The solution approach involves establishing relationships between the unknowns Ax, Ay, and the tension in cable BD, ultimately leading to the calculation of force F1.

PREREQUISITES
  • Understanding of vector forces in statics
  • Knowledge of equilibrium equations in 3D
  • Familiarity with unit vectors and their application
  • Ability to solve systems of equations
NEXT STEPS
  • Study the application of equilibrium equations in 3D statics problems
  • Learn how to derive unit vectors from force magnitudes
  • Practice solving systems of equations involving multiple unknowns
  • Explore advanced techniques for resolving forces in complex structures
USEFUL FOR

Students and professionals in engineering, particularly those specializing in structural analysis and statics, will benefit from this discussion.

keximaze
Messages
7
Reaction score
0
1. Three guy wires hold a pole BO as shown. The resultant R of the forces due to the three wires has a magnitude of 1000-N and is directed on the pole BO. Force F2 and F3 have a magnitude of 400-N and 500-N, respectively. The distance from point A to point D is 5-m. Find the tension in cable BD.



problem.jpg


Homework Equations


Summation of all the forces = 0
F1 + F2 + F3 + R = 0
F = F*(unit vector)

The Attempt at a Solution


On the solution below, I first established vectors F2 and F3 using the equation F=F*(unit vector). After that, I obtained a relation between Ax and Ay using the length AD.
I ended up with a set of 4 equations and 3 unknowns (the circled part below). I could get an answer but I am not sure if its right. Also, I believe that this is not the most practical way of solving the problem.
a.jpg
Could anyone please help me find a better way of solving this problem? Thanks in advance.
 
Physics news on Phys.org
There is no better way but you are almost there! You have three equations and two unknowns A_x and F_1

Solve Sum F_y=0 equation for A_x and plug into one of the other equations.
 
This question is a little confusing so one must be very careful to understand what is known and what is not known.

Once you are sure about what you know, you need to first find Ay, then Ax, then |F_1|. I won't give too much away, this is a very tough question.
 
vertigo said:
This question is a little confusing so one must be very careful to understand what is known and what is not known.

Once you are sure about what you know, you need to first find Ay, then Ax, then |F_1|. I won't give too much away, this is a very tough question.

Please explain what you mean by "one must be very careful to understand what is known and what is not known"...am I going on the right track or did I make a mistake on the first part?

More hints pleaseeeee.
 
You are doing this problem correctly! Everything looks good.

Now solve your expression "sum forces in Y direction=0" for A_x

Now that you have solved for A_x plug that result into expression for "sum of forces in Z direction = 0). You can solve for F_1

You could have plugged A_x into "Sum forces in x-direction = 0" as well, same result.

This problem is a bit of a bookkeeping nightmare but pretty straight forward in approach.
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

Similar threads

Replies
17
Views
3K
  • · Replies 5 ·
Replies
5
Views
3K
  • · Replies 5 ·
Replies
5
Views
4K
  • · Replies 1 ·
Replies
1
Views
2K
Replies
13
Views
2K
  • · Replies 7 ·
Replies
7
Views
8K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 13 ·
Replies
13
Views
2K
  • · Replies 4 ·
Replies
4
Views
2K
Replies
6
Views
2K