Resonance in forced oscillations

Click For Summary
SUMMARY

The discussion focuses on the conditions for resonance in forced oscillations described by the differential equation mx'' + cx' + kx = F(t), where F(t) = F_0 cos(ωt). It is established that resonance occurs under the condition of underdamping, specifically when the relationship (k - ω²m)² + ω²c² = 0 holds true. The participants clarify that the amplitude scaling factor F_0 does not influence the resonance condition, which is determined solely by the natural frequency of oscillation being equal to the driving frequency ω. The conclusion emphasizes that damping alters the resonance dynamics, preventing the denominator from reaching zero.

PREREQUISITES
  • Understanding of differential equations, specifically second-order linear equations.
  • Knowledge of concepts related to forced oscillations and resonance.
  • Familiarity with damping types: underdamping, overdamping, and critical damping.
  • Basic grasp of harmonic motion and natural frequency calculations.
NEXT STEPS
  • Study the effects of damping on resonance in mechanical systems.
  • Learn about the derivation and implications of the natural frequency formula: ω_n = √(k/m).
  • Explore the role of external forcing functions in oscillatory systems.
  • Investigate the mathematical techniques for solving second-order differential equations with damping.
USEFUL FOR

Students of physics and engineering, particularly those studying dynamics and vibrations, as well as educators looking to enhance their understanding of resonance phenomena in oscillatory systems.

green-beans
Messages
36
Reaction score
0

Homework Statement


Consider the differential equation:
mx'' + cx' + kx = F(t)
Assume that F(t) = F_0 cos(ωt).
Find the possible choices of m, c, k, F_0, ω so that resonance is possible.

Homework Equations

The Attempt at a Solution


I know how to deal with such problem when there is no damping, i.e. when we ignore cx'. In this case if cx'=0, resonance occurs when ω=k/m. However, now I have damping and as far as I understand resonance will be possible in case of underdamping, so when the complemtary function has complex solutions. My reasoning behind this was that in underdamping we get increasing oscillations (which is kind of the case with resonance). So, I solved the equation with the case of underdamping and resonance should occur when the denominator in my general solution is equal to 0. From what I got if (k-ω2m)2 + ω2c2=0 then resonance should take place. But this gives the relation between the unknowns and it does not take F_0 into consideration. So, I am not sure if I am right to assume ubderdaming and whether the solution is in fact the dependence relation.
P.S. I suspect this is wrong since I did not get a relation for F_0
Thanks a lot!
 
Physics news on Phys.org
I don't think F_0 should play, since the resonance should only appear when the right hand side is oscillating at the same rate as the homogeneous solution.
 
green-beans said:

Homework Statement


Consider the differential equation:
mx'' + cx' + kx = F(t)
Assume that F(t) = F_0 cos(ωt).
Find the possible choices of m, c, k, F_0, ω so that resonance is possible.

Homework Equations

The Attempt at a Solution


So, I solved the equation with the case of underdamping and resonance should occur when the denominator in my general solution is equal to 0. From what I got if (k-ω2m)2 + ω2c2=0 then resonance should take place. But this gives the relation between the unknowns and it does not take F_0 into consideration. So, I am not sure if I am right to assume ubderdaming and whether the solution is in fact the dependence relation.
P.S. I suspect this is wrong since I did not get a relation for F_0
Thanks a lot!
Obviously F_0 does not come into play, it's just a scaling coefficient.
With damping your denominator will never be zero. The idea is to find the "natural" oscillation frequency with damping [which is < √(k/m)], then make that equal to ω. That give you max. oomph per unit F_0.
 

Similar threads

Replies
17
Views
3K
Replies
9
Views
2K
  • · Replies 9 ·
Replies
9
Views
7K
  • · Replies 11 ·
Replies
11
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 7 ·
Replies
7
Views
2K
  • · Replies 11 ·
Replies
11
Views
2K
Replies
1
Views
1K
  • · Replies 1 ·
Replies
1
Views
3K
  • · Replies 1 ·
Replies
1
Views
2K