Resonant Frequency of AC Circuit with Coil, Capacitor and Resistance

Click For Summary
SUMMARY

The resonant frequency of an AC circuit comprising a coil, capacitor, and resistance is determined by the formula fR = 1/(2π√(LC)). To triple the resonant frequency, the product of inductance (L) and capacitance (C) must be reduced by a factor of 9. In the discussed circuit, a 160 microHenry inductor and a 160 picoFarad capacitor with a series resistance of 100 ohms yield a resonant frequency of 1 MHz and a quality factor (Q) of 10. The circuit's impedance phase transitions from +90 degrees to -90 degrees as the frequency sweeps from 300 kHz to 2 MHz.

PREREQUISITES
  • Understanding of AC circuit theory
  • Familiarity with resonant frequency calculations
  • Knowledge of inductance (L) and capacitance (C) values
  • Experience with quality factor (Q) in resonant circuits
NEXT STEPS
  • Study the impact of varying inductance and capacitance on resonant frequency
  • Learn about the effects of series and parallel resistance on Q factor
  • Explore resonance curves and their significance in circuit analysis
  • Investigate the use of swept frequency sources in testing AC circuits
USEFUL FOR

Electrical engineers, circuit designers, and students studying AC circuits who seek to deepen their understanding of resonant frequency and its implications in circuit performance.

xswtxoj
Messages
87
Reaction score
0
I don't understand when you have an AC Circuit that has a coil, capacitor and resistance. What factor will the resonant frequency change when the frequency is tripled?
 
Physics news on Phys.org
The resonant frequency of a circuit is equal to

fR= wR/(2 pi) = (1/(2 pi) 1/sqr(L C)

so to triple the resonant frequency, the product of L and C has to be decreased by a factor of 9.

The Q of the resonant circuit is equal to wRL/R for a series resiistance, or R/(wRL) for a parallel resistance.
 
I attach a resonance curve for a 160 microHenry inductance with a 160 picoFarad capacitor.
There is a series resistor of 100 ohms. The resonant frequency is 1 MHz, and sqrt(L/C) = 1000 ohms, so wL/R = Q = 10. The excitation is a swept frequency of a 1-amp current source from 300 kHz to 2 MHz. The dotted line is the phase of the circuit impedance, starting near + 90 degrees, and ending near - 90 degrees.
 

Attachments

Similar threads

  • · Replies 12 ·
Replies
12
Views
4K
  • · Replies 2 ·
Replies
2
Views
3K
  • · Replies 10 ·
Replies
10
Views
2K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 21 ·
Replies
21
Views
1K
  • · Replies 3 ·
Replies
3
Views
4K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 14 ·
Replies
14
Views
3K