Reverse Recovery Current of a diode

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SUMMARY

The discussion centers on the phenomenon of reverse recovery current in diodes when transitioning from forward to reverse bias. It is established that excess minority carriers stored in the P and N regions contribute to a temporary reverse current before the diode becomes fully blocked. The driving force behind this current is the electric field generated by the applied reverse voltage, which facilitates the movement of minority carriers back to their respective regions. This process involves both diffusion and recombination, leading to a negative current flow as the stored charges are cleared from the depletion zone.

PREREQUISITES
  • Understanding of diode operation principles, specifically forward and reverse bias.
  • Knowledge of minority carrier dynamics in semiconductor physics.
  • Familiarity with electric field concepts and their effects on charge carriers.
  • Basic grasp of charge recombination processes in semiconductors.
NEXT STEPS
  • Research "Diode reverse recovery time" to understand its implications in circuit design.
  • Study "Minority carrier lifetime" to grasp its impact on diode performance.
  • Explore "Charge carrier diffusion in semiconductors" for a deeper understanding of charge movement.
  • Investigate "Recombination mechanisms in P-N junctions" to learn about charge interactions.
USEFUL FOR

Electrical engineers, semiconductor physicists, and students studying diode behavior in electronic circuits will benefit from this discussion.

tonyjk
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Hello,

When the diode is in forward bias phase and suddenly we apply a reverse bias voltage, the diode takes time to be fully blocked because of the excess of minority charges that are stored in P and N region. Thus a reverse current appears in the diode for a short time before it is blocked. My question is, is this current a diffusion of the excess of minority carriers that are stocked? If yes, why this happens physically speaking? How the current suddenly becomes negative?

Thank you
 
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Hello again,

I am talking about this graph, which force is driving the excess of minority charges when the negative voltage is applied?
 

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Electric field force, F = qE. Minority carriers get stored in the depletion zone under forward bias. When the bias suddenly reverses, the E field of the external source points in a direction that forces the minority carriers back to their native material. Holes stored on the n side are forced to transit back to the p side and vice-versa. Similarly, electrons in the p side are forced back to the n side. Once the stored charge has been removed from the depletion zone and returned to its origin, the "tail current" ceases. Make sense?

Claude
 
tonyjk said:
Hello,

When the diode is in forward bias phase and suddenly we apply a reverse bias voltage, the diode takes time to be fully blocked because of the excess of minority charges that are stored in P and N region. Thus a reverse current appears in the diode for a short time before it is blocked. My question is, is this current a diffusion of the excess of minority carriers that are stocked? If yes, why this happens physically speaking? How the current suddenly becomes negative?

Thank you
When the potential is reversed the minority charges must be cleared out. This occurs both by dffusion and by recombination (holes in the n region recombine with electrons in the n region, and likewise with electrons in the p region). The negative current denotes that the sense of flow is opposite to that during forward bias.
 
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