1. The problem statement, all variables and given/known data The question asks me to revolve the the region bounded by the graphs y=√X y=0 and x=3 around a) the line x=3 and then b) around the line x=6 2. Relevant equations I know I am supposed to use the disk method or the washer method for this, which is ∏ ∫ R(y)^2-r(y)^2 from y=c to y=d. 3. The attempt at a solution for a, I set up R(y)=y^2. I set up the integral from y=0 to y= √3 ∏ ∫(y^2)^2 but when I plugged in the values I got 9.79 units cubed. In the back of my calculus book, however, it gives a different answer. I can't figure out what I did wrong. For b, I set R(y)=6 and r(y)=(6-y^2). I set up the the integral from y=0 to y=√3 ∏∫6^2-((6-y^2)^2) I got an answer of 55.5 units cubed. Again, this was not the correct answer given to me in the back of my book. I can't figure out what I did wrong. Any help would be greatly appreciated.