Rewriting Equation 15: Two Transverse Waves Moving in Opposite Directions

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SUMMARY

The discussion focuses on rewriting Equation 15 of the wave equation, specifically the expression y(x,t) = A(sin(2*pi*f*x)/v)*cos(2*pi*f*t), as a sum of two transverse waves moving in opposite directions. Participants emphasize the use of the superposition principle, represented as y(x,t) = f(x-ct) + g(x+ct), and the application of the trigonometric identity sin(Alpha)cos(Beta) = ½[sin(Alpha + Beta) + sin(Alpha − Beta] to separate the terms. The goal is to demonstrate how the wave equation can represent standing waves on a wire.

PREREQUISITES
  • Understanding of wave equations and their properties
  • Familiarity with trigonometric identities, particularly sin(A ± B)
  • Knowledge of the superposition principle in wave mechanics
  • Basic concepts of standing waves and their formation
NEXT STEPS
  • Study the derivation of the superposition principle in wave mechanics
  • Learn how to apply trigonometric identities in wave equations
  • Explore the concept of standing waves and their mathematical representation
  • Investigate the implications of wave interference and its applications
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Students studying physics, particularly those focusing on wave mechanics, as well as educators seeking to clarify the concepts of wave superposition and standing waves.

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Homework Statement



Show that the solution to the wave equation, Equation 15, can be rewritten as the sum of two transverse waves moving in opposite directions along the wire.

Equation 15:y(x,t) = A(sin(2*pi*f*x)/v))*cos(2*pi*f*t)


Homework Equations



Superposition: y(x,t) = f(x-ct) + g(x+ct)
Period: T = (1/f) = (2 * pi/omega)
Wavelength = (2* pi)/k

The Attempt at a Solution



I really just don't know where to start. Do I need a trig identity? I am completely not sure how to separate it into two terms that use like superposition for example. This equation shown above is not the standard wave equation but with variables substituted inside. I am trying to solve this or show for the topic of standing waves on a wire.
 
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You need to invert the trig identities for \sin(A\pm B) to derive a formula for the product \sin A \cos B.
 
So, what do you mean by inverting the trig identity?

Could you possibly, show me how to start this question?

sin Alpha cos β = ½[sin (Alpha + β) + sin (Alpha − β)] <--- This is a trig identity I should be using?

So would i just set Alpha = 2*pi*f*x/v and beta = 2*pi*f*t?
 
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