Riemann function for a second order hyperbolic PDE

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SUMMARY

The discussion focuses on finding the Riemann function for the second-order hyperbolic partial differential equation (PDE) given by the equation uxy + xyux = 0 in the region where x + y > 0. The proposed Riemann function, R(x,y;s,n), must satisfy specific conditions including Rxy - (xyR)x = 0, Rx = 0 on y = n, and Ry = xyR on x = s. A particular solution is derived by setting g(y) = 0, leading to the expression R = exp(xy²/2) H(x), where H(x) is an arbitrary function of x.

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Kate2010
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Homework Statement



Find the Riemann function for

uxy + xyux = 0, in x + y > 0
u = x, uy = 0, on x+y = 0

Homework Equations


The Attempt at a Solution



I think the Riemann function, R(x,y;s,n), must satisfy:

0 = Rxy - (xyR)x
Rx = 0 on y =n
Ry = xyR on x = s
R = 1 at (x,y) = (s,n)

But I don't know how to solve this beyond just spotting a solution.
 
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Kate2010 said:

Homework Statement



Find the Riemann function for

uxy + xyux = 0, in x + y > 0
u = x, uy = 0, on x+y = 0

Homework Equations





The Attempt at a Solution



I think the Riemann function, R(x,y;s,n), must satisfy:

0 = Rxy - (xyR)x
Rx = 0 on y =n
Ry = xyR on x = s
R = 1 at (x,y) = (s,n)

But I don't know how to solve this beyond just spotting a solution.

How about:
0 = Rxy - (xyR)x
g(y) = Ry - xyR

Pick g(y)=0, just to find a particular solution.
Ry = xyR
Ry/R = xy
ln R = xy2/2 + h(x)
R=exp(xy2/2) H(x)
 
Thanks :)
 

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