Riemann integrability of composite functions

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SUMMARY

The discussion centers on the Riemann integrability of composite functions, specifically proving that the composition of two Riemann integrable functions, where at least one is a step function, is also Riemann integrable. The user successfully demonstrated the case where g is a step function but sought assistance for the scenario where f is a step function. The conclusion drawn is that the set of discontinuities of the composite function f(g(x)) has measure zero, confirming the integrability under the given conditions.

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  • Understanding of Riemann integrability
  • Knowledge of step functions
  • Familiarity with the concept of measure zero sets
  • Basic principles of composite functions
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  • Study the properties of Riemann integrable functions
  • Explore the implications of step functions in integration
  • Investigate the relationship between Riemann and Lebesgue integration
  • Learn about the measure theory and its application in integration
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Mathematics students, educators, and researchers focusing on real analysis, particularly those interested in integration theory and the properties of composite functions.

darkreignmoon
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Hi, I'm stuck on this problem here about composite function, help is appreciated:

Let g : [a,b] -> [c,d] be Riemann integrable on [c,d] and f : [c,d] -> R is Riemann integrable on [c,d]. Prove that f o g is Riemann integrable on [a,b] if either f or g is a step function

I was able to solve the part where g is a step function but if f is a step function then I don't know how to approach this.
 
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Consider the set of discontinuities of fog. f(g(x)) can be discontinuous when either g is discontinuous(say on the set G) or when it attains a 'bad' value in the domain of f(say in F).
Both F,G have measure 0 as f,g are Riemann integrable.FXG has measure 0 if f is a step function & hence the result.
I wonder what happens in case of Lebesgue integration.
 

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